3m^2=-4m+39

Solution for 3m^2=-4m+39 equation:

3m^2=-4m+39

We move all terms to the left:

3m^2-(-4m+39)=0

We get rid of parentheses

3m^2+4m-39=0

a = 3; b = 4; c = -39;
Δ = b2-4ac
Δ = 42-4·3·(-39)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-22}{2*3}=\frac{-26}{6}
=-4+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+22}{2*3}=\frac{18}{6}
=3
$